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4u^2-17u+15=0
a = 4; b = -17; c = +15;
Δ = b2-4ac
Δ = -172-4·4·15
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-7}{2*4}=\frac{10}{8} =1+1/4 $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+7}{2*4}=\frac{24}{8} =3 $
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